ok i was curios about something.. ok so lets say there is a moon i want to destroy and i am launching enough rips for a 25% chance what are the chances i will lose my ripsand what is the formula for the odds of losing rips in the siplest form

Cypher wrote:Backfire = ROUND(SQRT(MOONSIZE)/2.0,0)

Here you go

Hope this helps

so the moon size is 9502.... but can you explain what round and sqrt are mabey use this moon size to show me an example.. lets say i will send 98 rips for a 25% chance of destruction can you show me the breakdown of the formula... I know I know i ask alot

truction chances for diameter of 9,502
99%: 1,541 Death stars needed.
98%: 1,510 Death stars needed.
97%: 1,480 Death stars needed.
96%: 1,449 Death stars needed.
95%: 1,419 Death stars needed.
90%: 1,274 Death stars needed.
85%: 1,136 Death stars needed.
80%: 1,006 Death stars needed.
75%: 885 Death stars needed.
50%: 393 Death stars needed.
25%: 98 Death stars needed.

The probability of the destruction of the deathstar fleet is 49 %

there is a 25 percent chance that it fail, incase it fails then there is a 49 % chance that your death stars go kaboom!

You round the result of the square root of the moon size divided by two. So in this case the square root of 9502 is 97.48, which you divide by two: 48.74; rounded up is 49%

Weresloth wrote:You round the result of the square root of the moon size divided by two. So in this case the square root of 9502 is 97.48, which you divide by two: 48.74; rounded up is 49%

ok explaining like that i get it lol

Just remember that the number of RIPs has no bearing

ahh so even at a 99% chance of moon destruction i would still have a 49% chance of losing my rips

Exactly

Wow i did not kniw thar thanks