Zorg Empire

As with all things on these forums, there's lots of information. But it is split into fractions and one has to piece together the picture.

As I understand it, to do an effective MoonShot with an Alliance partner, it would go something like this:

Abel - is assisting
Moony - is getting the Moon

Abel builds enough Recylers to harvest a failed Moonshot and Enough attacking ships to take out 50 Battleships.
Moony builds 50 Battleships and has no defense (as a favor to Abel)

Abel Attacks Moony and creates DF.

No Moon? Abel collects the DF with his Recyclers and delivers it back to Moony to rebuild his Battleships

Abel Attacks Moony and creates DF, again.

New Moon! Cheers all around! Now Moony helps Abel!

Do I have it right? If not, can you be specific?

Thanks,
-DarkMoon

A moon shot is a shot that tries to get another player a moon. The maximum moon chance is 19%. And any df more than 1.900.000 DF combined gets u 19% max moon shot chance. Please note consecutive moon shots are independent of each other. Previous hits will not contribute to the next moon shot (MS) in anyway ... by chance or by the addition of DF. Usually one will get 1 moon per 5 chances. But the standing record i think is 63 shots no moon so far. So dont get disappointed or think that the game is rigged if you dont get moon. You are just not lucky enough

Some of the more popular moon shot fleets are ....

Espionage probes 3.726
BS 53
LC 212
LF 1056

You need 96 recs to collect 1 moon shot worth df. For a player defending the moon shot you need

3000 LLs + 2 domes (if the wsa difference is not more that 3 between attacker and defender else you need 4000 LLs)

or 200 BC/300 BS fleet if it is a defenseless planet or attack the planet that is left with the moon shot fleet.

>Who collects the DF?

If it is a moon shot exchange then usually either attacker collects his df or defender collects df at his defending planet.

How the df can be collected it depends on the player agreement. But if it is not a moon shot exchange then defender should manage to get the attacker his df back if attacker is not collecting.

Hope that is clear enough.

Excellent, I think that's very clear (I'll find out when I try to use it!)

BTW. The odds of 63 failed moonshots at 19% chance on each shot... it's approximately the same as tossing 19 consecutive heads on a coin! If a player did 63 consecutive moonshots every day, it would take 1436 years before he missed 63 times in a row.

I think either the player did not have 19% chance every time or this is an Urban Myth!

Here are the probabilities of successful moonshot by number of tries (assumes 19% chance each time):

1 19%
2 34%
3 47%
4 57%
5 65%
6 72%
7 77%
8 81%
9 85%
10 88%

-DarkMoon

you missed something

as i said the moon shots do not carry through any advantage or disadvantage to the next moon shot each are independent of the last try. As there is no dependencies the chances are actually always 19% (if the right number of ships used).

as you said for tossing a coin your chances of getting a head is 50% on each try it wont change on consecutive tries unless last try some how contributed to the this one. you always either get head or tail.

as long as that remains you may never get heads no matter how many times you try.

No, I didn't miss anything. I'll make a big deal of this because I think it is important for people to know how long it will take to get a moon....

The probabilities I posted are based on independent trials.

The probability of getting a Moon in two trials is .19 + .81 * .19 (that is, you could get it on the first trial 19% or you could miss the first and get the second .81 * .19) the sum of these two is .34, the odds of getting a moon in two trials.


You can prove this to yourself. Toss a coin three times. The odds of getting a head at least in each set of three is...
.5 + .5 *.5 + .5*.5*.5 = .875 or 87.5%

The events are independent. But you have a very high odds of getting a head at least once in three tosses.
Do 10 sets of three and see if you don't get at least one head in 9 of the 10 sets.

-DarkMoon

Incidentally, I could confirm all of your fleet sizes except Espionage Probes. My math shows they produce 240 M and 1800 Crystal for 2040 DF...

1,900,000 / 2040 = 932 rounded up. (Not 3.726)

Am I missing something? Each of the other three came out exactly when I checked them on my own.

Thanks

that would be my bad, what i posted for probes were for extreme server. you are right the probe count for standard/speed server is low cause on both servers due to heavy cost of crystals per probes the structure point is a bit higher.

For,
> extreme server Espionage probes 3.726
> speed/standard server Espionage probes 932